[Draft] Find maximum products which can picked up from pile of products with increasing count of products pick up

find-max-prods-pick-from-pile-of-prods.js

const removeProductsFromPile = (pileOfProducts, indexStart = 0, endIndex = pileOfProducts.length, maxProducts, reduceBy = 'max') => {
    pileOfProducts.map((product, currentProductIndex) => {
        
        const productsLeftInPile = product - 1;
        let lastProductsPickCount;
        for (let nextProductIndex = currentProductIndex + 1; nextProductIndex < pileOfProducts.length; nextProductIndex++) {
            const nextPileOfProduct = product[nextProductIndex];
            if (nextPileOfProduct > product) {
                maxProducts = product + nextPileOfProduct;
            }
            if (nextPileOfProduct < product) {
                maxProducts = nextPileOfProduct + nextPileOfProduct - 1;
            }
            removeProductsFromPile(product)
        }
    });
    return false;
}


function findMaxProducts(pileOfProducts) {
    let maxProducts = 0;
    maxProducts = removeProductsFromPile(product, 1);
}

function main() {
    console.log('Test case passed:', findMaxProducts([2, 9, 4, 7, 5, 2]) === 16)
}


{/* <ul>
	<li>Choose subarray from indices (1, 2) and pick&nbsp;products [2, 9] respectively from each index, which is 11 products.</li>
	<li>Choose subarray from indices (1, 4) and pick&nbsp;products [2, 3, 4, 7] , which is 16 products.</li>
	<li>Choose subarray from indices (1, 5) and pick&nbsp;products [1, 2, 3, 4, 5], which is 15 products.</li>
</ul> */}