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Solutions to Leet Code Problems
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| function isPalindrome(num: number): boolean { | |
| let reversedNum = 0; | |
| let x = num; | |
| while (x > 0) { | |
| reversedNum = reversedNum * 10 + x % 10; | |
| x = x / 10 >> 0; // >> removes decimal | |
| } | |
| return reversedNum === num; | |
| }; |
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| const romanNumberMap = { | |
| 'I': 1, | |
| 'V': 5, | |
| 'X': 10, | |
| 'L': 50, | |
| 'C': 100, | |
| 'D': 500, | |
| 'M': 1000 | |
| } | |
| const isExceptionalRoman = (currentLetter: string, nextLetter: string): boolean => { | |
| return currentLetter === 'I' && ['V', 'X'].includes(nextLetter) | |
| || currentLetter === 'X' && ['C', 'L'].includes(nextLetter) | |
| || currentLetter === 'C' && ['M', 'D'].includes(nextLetter) | |
| } | |
| function romanToInt(s: string): number { | |
| let output = 0; | |
| let i = 0; | |
| while (i < s.length) { | |
| const nextLetter = s[i + 1]; | |
| const currentLetter = s[i]; | |
| if (isExceptionalRoman(currentLetter, nextLetter)) { | |
| output += romanNumberMap[nextLetter] - romanNumberMap[currentLetter]; | |
| i += 2; | |
| } else { | |
| output += romanNumberMap[currentLetter]; | |
| i++; | |
| } | |
| } | |
| return output; | |
| }; |
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| function twoSum(nums: number[], target: number): number[] { | |
| const numbersHashMap = {} as Record<number, number>; | |
| for (let i = 0; i < nums.length; i++) { | |
| const num = nums[i]; | |
| const diff = target - num; | |
| if (diff in numbersHashMap) { | |
| return [numbersHashMap[diff], i]; | |
| } | |
| numbersHashMap[num] = i; | |
| } | |
| return []; | |
| }; |
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