Calculate Number of day created by Auttawut Wiriyakreng - https://repl.it/GBrU/0

Calculate Number of day.py

import math
import time
import datetime

def tm(yy,mm,dd):
  s = str(dd) + "/" + str(mm) + "/" + str(yy)
  return time.mktime(datetime.datetime.strptime(s, "%d/%m/%Y").timetuple())

y = 2017
m = 2
d = 2

ynow = 2017
mnow = 3
dnow = 1


t0 = y*12 + m - 1     # total months for birthdate.
t = ynow*12 + mnow - 1   # total months for Now.
dm = t - t0             # delta months.    
if dnow >= d:
  print('Year : ' + str(math.floor(dm/12)) + ' Months : ' + str(dm%12) + ' Day : ' +  str(dnow-d))
  
else:
  dm = dm - 1
  t = t - 1
  
  print(str(tm(ynow,mnow,dnow)) + ' ' + str(tm(math.floor(t/12), (t%12)+1, d)) + ' ' + str(d))
  
  print(str(math.floor(t/12)) + str(t%12+1) + str(d))
   
  if ((math.floor(t/12)%4 == 0 and math.floor(t/12)%100 != 0) or math.floor(t/12) % 400 == 0):
    d = d
    print('Year : ' + str(math.floor(dm/12)) +  ' Months : ' + str(dm%12) + ' Days : ' + str((tm(ynow,mnow,dnow) - tm(math.floor(t/12), (t%12)+1, d))/60/60/24))
  else:
    #allDay = (tm(ynow,mnow,dnow) - tm(math.floor(t/12), (t%12), d))/60/60/24
    allDay = (tm(ynow,mnow,dnow) - tm(y, m, d))/60/60/24
    print(allDay)
    if(m+1 > 12):
      m = 0
      y = y + 1
      
    #print(str(tm(ynow,mnow,dnow)) + " " + str(tm(y, m, d)))
    
    betDay = ( (tm(ynow,mnow,1) - 86400) - (tm(y, m+1, 1)) ) /60/60/24
    print(allDay-betDay)
    print('Year : ' + str(math.floor(dm/12)) +  ' Months : ' + str(dm%12) + ' Days : ' + str(allDay-betDay-1))