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July 28, 2016 19:47
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This program takes a text file with a list of words and checks how many words can be formed with the letters provided by command line argument.
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import java.io.BufferedReader; | |
import java.io.File; | |
import java.io.FileNotFoundException; | |
import java.io.FileReader; | |
import java.io.IOException; | |
import java.util.ArrayList; | |
import java.util.Arrays; | |
import org.apache.commons.lang.StringUtils; | |
public class AnagramFinder { | |
/** | |
* @param args | |
*/ | |
public static void main(String[] args) { | |
if(args.length == 2) { | |
AnagramFinder.findAnagrams(args[0], new File(args[1])); | |
} | |
else { | |
System.out.println("Invalid number of arguments!"); | |
} | |
} | |
public static boolean isAnagram(String word, char[] validLetters) { | |
ArrayList<String> currentChars = new ArrayList<String>(); | |
char[] wordChars = word.toCharArray(); | |
for(char _char : wordChars) | |
currentChars.add(String.valueOf(_char)); | |
int validLetterCount = 0; | |
for(char _char : validLetters) { | |
String value = String.valueOf(_char); | |
if(currentChars.contains(value)) | |
validLetterCount++; | |
currentChars.remove(value); | |
} | |
return validLetterCount == word.length(); | |
} | |
public static void findAnagrams(String word, File wordsFile) { | |
try { | |
System.out.println("Reading file"); | |
BufferedReader reader = new BufferedReader(new FileReader(wordsFile)); | |
char[] validLetters = word.toCharArray(); | |
System.out.println("Searching anagrams"); | |
ArrayList<String> lines = new ArrayList<String>(); | |
String line; | |
while((line = reader.readLine()) != null) | |
if(line.length() == word.length()) | |
if(isAnagram(line, validLetters)) | |
System.out.println("Anagram found: " + line); | |
} | |
catch (FileNotFoundException e) { | |
System.out.println("Could not find file!"); | |
} | |
catch (IOException e) { | |
// TODO Auto-generated catch block | |
System.out.println("Could not process file!"); | |
} | |
} | |
} |
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