Created
December 6, 2017 15:33
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Longest Common Subsequence
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| def lcs(s1, s2): | |
| def lcs_(s1, s2, m, n): | |
| if (m < 0) or (n < 0): | |
| return 0 | |
| elif s1[m] == s2[n]: | |
| return 1 + lcs_(s1, s2, m - 1, n - 1) | |
| else: | |
| return max(lcs_(s1, s2, m - 1, n), | |
| lcs_(s1, s2, m, n - 1)) | |
| return lcs_(s1, s2, len(s1) - 1, len(s2) - 1) |
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