Created
August 15, 2016 13:57
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Calculate modulus of sum of to large integers with prime number
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#include <iostream> | |
#include <string> | |
using namespace std; | |
int main () { | |
string num1, num2, res, len1; | |
cout << "Enter Number: "; cin >> num1; | |
cout << "Enter Number: "; cin >> num2; | |
int prime; | |
cout << "Enter prime number: "; | |
cin >> prime; | |
int carry=0, sum; | |
int i = num1.length()-1; | |
int j = num2.length()-1; | |
/* sum from last digits untill one of numbers is reached to less than zero index */ | |
for (; i >= 0 && j>=0 ; i--, j--) { | |
sum = (carry+(num1[i]-'0')+(num2[j]-'0')); | |
carry = sum/10; | |
sum = sum%10; | |
res.insert(0, 1, sum+'0'); | |
} | |
/* add number which is left */ | |
while(i>=0) { | |
sum = (carry+num1[i]-'0'); | |
carry = sum/10; | |
sum = sum%10; | |
res.insert(0, 1, sum+'0'); | |
i--; | |
} | |
while(j>=0) { | |
sum = (carry+num2[j]-'0'); | |
carry = sum/10; | |
sum = sum%10; | |
res.insert(0, 1, sum+'0'); | |
j--; | |
} | |
/* if carry left then add it to result number */ | |
if (carry) | |
res.insert(0, 1, carry+'0'); | |
/** | |
* Modular Arithmetic for finding modulo | |
* remainder = 0 | |
* for each digit from begining | |
* remainder = (10 * remainder + current_digit) % num; | |
*/ | |
carry = 0; | |
for (i=0; i < res.length(); i++) { | |
carry = (10*carry + (res[i]-'0'))%prime; | |
} | |
cout << "("; | |
cout << num1 << "+" << num2 << ") % " << prime << " = " << carry << "\n"; | |
return 0; | |
} |
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