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December 28, 2014 05:59
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Dynamic Programming Example
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''' | |
How many ways can the set of numbers from 1 to N be partitioned into two | |
subsets in such a way that the sum of both subsets is equal? | |
Hint 1. For each partitioning, the sum of each subset will be the same value | |
Hint 2. This value is the sum from 1 to N divided by 2. (N * (N + 1) / 2) / 2 | |
Hint 3. The problem has been reduced to, "How many subsets of a given set sum | |
to a specific value?". Note that once we have this number of subsets, we | |
divide it by 2, because each subset is a member of pair that satisfies the | |
original question. | |
Hint 4. Start with a Dynamic Programming array that holds the number of subsets | |
that sum to values from 0 to T, where T is the target value as computed above. | |
The indicies of the array will be target sums and the values are the number | |
of subsets that sum to these values. | |
Hint 5. Add numbers to the set one at a time, updating the DP array with the | |
current count for each target | |
Hint 6. After adding all of the elements to the set the answer will be the | |
count for the target value | |
''' | |
# Solution | |
import sys | |
def num_subsets_with_sum(s, target): | |
dp = [0 for i in xrange(0, target + 1)] | |
dp[0] = 1 | |
for num in s: | |
for curr_target in xrange(target, num - 1, -1): | |
if (dp[curr_target - num]): | |
dp[curr_target] += dp[curr_target - num] | |
return dp[target] | |
def main(): | |
n = int(sys.stdin.readline()) | |
s = set([i for i in xrange(1, n + 1)]) | |
series_sum = n * (n + 1) / 2 | |
if series_sum % 2 == 1: | |
print 0 | |
sys.exit(0) | |
target = series_sum / 2 | |
print num_subsets_with_sum(s, target) / 2 | |
if __name__ == "__main__": | |
main() | |
''' | |
Example: | |
Given the set {1, 2, 3, 4, 5, 6, 7}, how many ways are there to produce the sum 14? | |
Technique: | |
Build up the set one element at a time, while updating a DP array | |
Number of ways to produce the sum: | |
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 | |
1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 (initial DP array) | |
1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 (iteration 1: add 1 to the set) | |
1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 (iteration 2: add 2 to the set) | |
1 1 1 2 1 1 1 0 0 0 0 0 0 0 0 (iteration 3: add 3 to the set) | |
1 1 1 2 2 2 2 2 1 1 1 0 0 0 0 (iteration 4: add 4 to the set) | |
1 1 1 2 2 3 3 3 3 3 3 2 2 1 1 (iteration 5: add 5 to the set) | |
1 1 1 2 2 3 4 4 4 5 5 5 5 4 4 (iteration 6: add 6 to the set) | |
1 1 1 2 2 3 4 5 5 6 7 7 8 8 8 (iteration 7: add 7 to the set) | |
In each iteration, previous values of the DP array are used to calculate new values, | |
given the item being added to the set. | |
''' |
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