Create the smallest solution to take the given data hash and produce the desired output (using pure Ruby stdlib)

hash_challenge.rb

# Source data
#
data = {
  name: 'John Smith',
  age: 45,
  address: '123 Here St',
  email: '[email protected]'
}

# Code here..

# Desired output
#
# {:name=>"John Smith", :email=>"[email protected]"}

data.slice(:name, :email)

Oh, that's cheating - it's an Active Support core extension ;-)

I't must be possible to do it more concisely than this:

data.select {|k,v| [:name, :email].include? k}

data.except(:age, :address)

_.pick(data, 'name', 'email')

@stuliston Oh, it's cheating as well. it's javascript!!!

@ashmckenzie in fairness, I only added the 'using Ruby stdlib' after this :)

That's an interesting method, @jdunwoody...

I made this just for you Ash. Extra special taco bell code.

!/bin/bash

NAME=cat test |tail +2 | cut -d: -f2 |cut -d\' -f2|head -1
EMAIL=cat test |tail +5 | cut -d: -f2 |cut -d\' -f2|head -1
echo "{:name=>$NAME, :email=>$EMAIL}"

*'test' is the input file
*this is a joke, but it works

@ashmckenzie Code named 'Fiery Doritos Locos Tacos Supreme'

data.delete_if {|k| [:age, :address].include? k}

Building on @pmoran's, but in the opposite way, assuming you know what you want and not necessarily what you don't want:

data.keep_if {|k| [:name, :email].include? k}

data.select { |k,v| k =~ /^(n|e)/ }

@ashmckenzie absolutely shameful :)

@ashmeckenzie neat!

Because all the neat solutions were taken (I was going with Stu). I give you:

[:name, :email].map {|k| Hash[k, data[k]] }.inject(:update)

@ashmckenzie BAM, #map and #inject !

@gabrielrotbart obfuscation is the best solution

Here's the winning solution*

> data.win
=> {:name=>"John Smith", :email=>"[email protected]"}

*assuming you're using my personally-patched ruby

class Hash
  def win
    {:name=>"John Smith", :email=>"[email protected]"}
  end
end