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April 3, 2019 17:28
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CSS Diner Solutions
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| http://flukeout.github.io/ | |
| #01 plate | |
| #02 bento | |
| #03 #fancy | |
| #04 plate > apple | |
| #05 #fancy pickle | |
| #06 .small | |
| #07 orange.small | |
| #08 bento orange.small | |
| #09 plate, bento | |
| #10 * | |
| #11 orange.small, pickle, plate > apple | |
| #12 plate + apple | |
| #13 bento ~ pickle | |
| #14 plate > apple | |
| #15 plate orange:first-child | |
| #16 plate *:only-child | |
| #17 #fancy *:last-child , plate + pickle | |
| #18 plate:nth-child(3) | |
| #19 bento:nth-last-child(4) | |
| #20 apple:first-of-type | |
| #21 plate:nth-of-type(2n) | |
| #22 plate:nth-of-type(2n+3) | |
| #23 plate apple.small:only-of-type | |
| #24 orange:last-of-type , apple:last-of-type | |
| #25 bento:empty | |
| #26 apple:not(.small) |
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Siguiendo al estructura del ejercicio, la respuesta correcta sería una combinación de selectores. El concepto de selector de hijos se puede usar pero debería de dejarse para más adelante, para no cargarte la didactica del ejercio (concepto ⇾aplicación).