Order an array of objects based on another array order ES6

mapOrderES6.js

/*
 Sort array of objects based on another array
 Original function:

function mapOrder (array, order, key) {
  array.sort( function (a, b) {
    var A = a[key], B = b[key];
    if (order.indexOf(A) > order.indexOf(B)) {
      return 1;
    } else {
      return -1;
    }
  });
  return array;
};
 *******
 * ES6:
 *******/
mapOrder = (array, order, key) => {
  return array.sort((a, b) => {
    const A = a[key],
          B = b[key];
    return order.indexOf(A) > order.indexOf(B) ? 1 : -1;
  });
};


/**
 * Example:
 */

var item_array, item_order, ordered_array;

item_array = [ 
  { id: 2, label: 'Two' }
, { id: 3, label: 'Three' }
, { id: 5, label: 'Five' }
, { id: 4, label: 'Four' }
, { id: 1, label: 'One'}
];

item_order = [1,2,3,4,5];

ordered_array = mapOrder(item_array, item_order, 'id');

console.log('Ordered:', JSON.stringify(ordered_array));