Check some date and datetime functioning

date_datetime.py

from datetime import datetime, timedelta

date1 = datetime.now()
date2 = date1 + timedelta(days=1)

print(date1)
print(date2)

print(date1 > date2)

print(date1.date())
print(date2.date())
print('date1.date() > date2.date():', date1.date() > date2.date())
print('date1.date() < date2.date():', date1.date() < date2.date())

print('date2 - date1:', date2 - date1)
print('date2.date() - date1.date():', date2.date() - date1.date())
print('date2 - date1 type:', type(date2 - date1))
print('date2.date() - date1.date() type:', type(date2.date() - date1.date()))

print('date2 - date1 days:', (date2 - date1).days)
print('date2.date() - date1.date() days:', (date2.date() - date1.date()).days)

print('date2 - date1 days type:', type((date2 - date1).days))
print('date2.date() - date1.date() days type:', type((date2.date() - date1.date()).days))

2022-04-29 08:37:49.524254
2022-04-30 08:37:49.524254
False
2022-04-29
2022-04-30
date1.date() > date2.date(): False
date1.date() < date2.date(): True
date2 - date1: 1 day, 0:00:00
date2.date() - date1.date(): 1 day, 0:00:00
date2 - date1 type: <class 'datetime.timedelta'>
date2.date() - date1.date() type: <class 'datetime.timedelta'>
date2 - date1 days: 1
date2..date() - date1.date() days: 1
date2 - date1 days type: <class 'int'>
date2..date() - date1.date() days type: <class 'int'>