Created
January 3, 2013 15:11
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`break` in block
原来`break`拥有跳出所有block的能力
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def a(&block) | |
puts 'enter a' | |
b &block | |
puts 'exit a' | |
end | |
def b(&block) | |
puts 'enter b' | |
c &block | |
puts 'exit b' | |
end | |
def c(&block) | |
puts 'enter c' | |
d &block | |
puts 'exit c' | |
end | |
def d(&block) | |
puts 'enter d' | |
block[] | |
puts 'exit d' | |
end | |
a do | |
puts 'enter block' | |
break | |
puts 'exit block' | |
end | |
# output: | |
# enter a | |
# enter b | |
# enter c | |
# enter d | |
# enter block |
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参考这里
http://stackoverflow.com/questions/4702211/are-return-and-break-useless-inside-a-ruby-block-when-used-as-a-callback
前面的都不用看