palindrom check using std::deque

isPalindromeWithDeque.cpp

#include <iostream>
#include <deque>

using namespace std;

bool isPalindrome(const char *in) {
	deque<char> dq;
	
	while (*in != '\0') {
		dq.push_back(*in);
		in++;
	}
	
	while (!dq.empty()) {
		
		if (dq.size() == 1)
		 return true;
		
		if (dq.front() !=  dq.back())
		    return false;
				
		dq.pop_back(); dq.pop_front();
	}
	
	return true;
}

int main() {
	string s = "t";
	
	cout << isPalindrome(s.c_str());
	
	return 0;
}