Timeout any function

timeout.py

from functools import wraps
import errno
import os
import signal
import time

# timeout any function in given seconds
# solution from http://stackoverflow.com/questions/2281850/timeout-function-if-it-takes-too-long-to-finish

class TimeoutError(Exception):
    pass

def timeout(seconds=10, error_message=os.strerror(errno.ETIME)):
    def decorator(func):
        def _handle_timeout(signum, frame):
            raise TimeoutError(error_message)

        def wrapper(*args, **kwargs):
            signal.signal(signal.SIGALRM, _handle_timeout)
            signal.alarm(seconds)
            try:
                result = func(*args, **kwargs)
            finally:
                signal.alarm(0)
            return result

        return wraps(func)(wrapper)

    return decorator

@timeout(5)
def long_f():
    for i in range(10):
        print(i)
        time.sleep(1)

long_f()

expected output

0
1
2
3
4
Traceback (most recent call last):
  File "timeout.py", line 35, in <module>
    long_f()
  File "timeout.py", line 20, in wrapper
    result = func(*args, **kwargs)
  File "timeout.py", line 33, in long_f
    time.sleep(1)
  File "timeout.py", line 14, in _handle_timeout
    raise TimeoutError(error_message)
__main__.TimeoutError: Timer expired