Created
March 7, 2018 20:00
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def f(x, y): | |
z = x * y | |
return z | |
# Operator overloading | |
adjoints = { | |
'mul': lambda dz, x, y: dz * y, dz * x | |
} | |
def f(x, y): | |
# Forward | |
tape.append(('mul', x, y)) | |
z = x * y | |
# Backward | |
dz = 1 | |
op, *args = tape.pop() | |
dx, dy = adjoints[op](*args) | |
return dx, dy | |
# Tape-based SCT | |
def f(x, y): | |
# Forward | |
tape.append(x) | |
tape.append(y) | |
z = x * y | |
# Backward | |
dz = 1 | |
y = tape.pop() | |
x = tape.pop() | |
dx = dz * y | |
dy = dz * x | |
return dx, dy | |
# Backpropagator SCT | |
def f(x, y): | |
# Forward | |
z = x * y | |
def df(dz): | |
return dz * y, dz * dz * x | |
# Backward | |
dz = 1 | |
dx, dy = df(dz) | |
return dx, dy | |
# Delimited continuation SCT | |
def f(x, y): | |
# This forward step gets automatically captured by the shift/reset control operators | |
def mul(k): | |
# One step forward | |
z = x * y | |
# Rest of the forward pass | |
k(z) | |
# One step backward | |
x.d = z.d * y | |
y.d = z.d * x | |
# Start backward | |
z.d = 1 | |
# Rest of the forward pass is nothing | |
mul(lambda x: None) | |
return x.d, y.d |
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