Python List Comprehension: Find all of the numbers from 1-1000 that have a 3 in them

findThree.py

'''
Find all of the numbers from 1-1000 that have a 3 in them
'''

three = [n for n in range(0,1000) if '3' in str(n)]
print(three)

You could also do it this way:
lst_include3=list(filter(lambda x: '3' in str(x), range(1,1000)))
print(lst_include3)

solution = [a for a in range(1, 1000+1) if '3' in str(a)]

num_3 = [num for num in range(1001) if '3' in str(num)]
print(num_3)

r=[x for x in range(1,1001) if x%10==3 or (x//10)%10==3 or (x//100)%10==3]
print(r)

list=[i for i in range(1,1001) if '3' in str(i) ]

num = print([n for n in range(1,1001) if '3' in str(n)]

Output: [3, 13, 23, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 43, 53, 63, 73, 83, 93, 103, 113, 123, 130, 131, 132, 133, 134, 135, 136, 137, 138, 139, 143, 153, 163, 173, 183, 193, 203, 213, 223, 230, 231, 232, 233, 234, 235, 236, 237, 238, 239, 243, 253, 263, 273, 283, 293, 303, 313, 323, 330, 331, 332, 333, 334, 335, 336, 337, 338, 339, 343, 353, 363, 373, 383, 393, 403, 413, 423, 433, 443, 453, 463, 473, 483, 493, 503, 513, 523, 533, 543, 553, 563, 573, 583, 593, 603, 613, 623, 633, 643, 653, 663, 673, 683, 693, 703, 713, 723, 733, 743, 753, 763, 773, 783, 793, 803, 813, 823, 833, 843, 853, 863, 873, 883, 893, 903, 913, 923, 933, 943, 953, 963, 973, 983, 993]

l = [x for x in range(1001) if '3' in str(x)]
print(l)