Returning a scrabble score (without letter multiplier squares).

scrabble_score.py

score = {"a": 1, "c": 3, "b": 3, "e": 1, "d": 2, "g": 2,
         "f": 4, "i": 1, "h": 4, "k": 5, "j": 8, "m": 3,
         "l": 1, "o": 1, "n": 1, "q": 10, "p": 3, "s": 1,
         "r": 1, "u": 1, "t": 1, "w": 4, "v": 4, "y": 4,
         "x": 8, "z": 10}


def scrabble_score(word):
    word = word.lower()
    tally = 0
    for i in word:
        tally += score[i]
        return tally

print scrabble_score("helix")

score = {"a": 1, "c": 3, "b": 3, "e": 1, "d": 2, "g": 2,
"f": 4, "i": 1, "h": 4, "k": 5, "j": 8, "m": 3,
"l": 1, "o": 1, "n": 1, "q": 10, "p": 3, "s": 1,
"r": 1, "u": 1, "t": 1, "w": 4, "v": 4, "y": 4,
"x": 8, "z": 10}
def scrabble_score(word):
lst = []
word = word.lower()
for letter in word:
for key in score:
if letter == key:
lst.append(score[key])
else:
continue
return sum(lst)

print scrabble_score('pie')