Created
September 6, 2014 12:34
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Generate pseudo-random passwords from a built in word list.
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#!/usr/env python | |
''' | |
Author: Ben Hosmer | |
License: Unlicense http://unlicense.org/ | |
Note: This is pseudo-random meaning don't rely on it for high-security! | |
''' | |
import random | |
import os | |
import sys | |
import linecache | |
import string | |
# The number of words to use from the list. | |
# Defaults to 2 if no value was given. | |
if len(sys.argv) > 1: | |
numofwords = int(sys.argv[1]) | |
else: | |
numofwords = 2 | |
platform = sys.platform | |
# OS X Default Word list | |
if platform == 'darwin': | |
if os.path.exists('/usr/share/dict/words'): | |
wordlist = '/usr/share/dict/words' | |
#print 'Using OS X Wordlist... ' + wordlist | |
# Linux Word List | |
elif platform == 'linux2': | |
if os.path.exists('/usr/share/dict/words'): | |
wordlist = '/usr/share/dict/words' | |
print 'linux wordlist found' | |
# Choose random words from the list to use. | |
with open(wordlist) as lines: | |
words = [] | |
count = sum(1 for line in lines) | |
for i in range(numofwords): | |
words.append(linecache.getline(wordlist, random.randint(1, count))) | |
# Skip adding a special character to the first word, but add it to delimit | |
# each additional word. | |
words[1:] = [string.punctuation[random.randint(0, len(string.punctuation) -1)] + word for word in words[1:]] | |
# Clean up the list removing newlines and squash them all together in a string. | |
print ''.join([str(item.replace('\n', '')) for item in words]) |
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