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June 19, 2013 17:26
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My own notes in explains the chain.exs in Programming Elixir, Chapter 12
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defmodule Chain do | |
# There are a couple of interesting things to note in this example. | |
# Take a look at the 'counter' function: | |
# It takes in a pid, NOT 'n'. | |
# 'n' will be received in the form of a message (i.e. pid <- msg ) | |
# In a sense, we are 'loading/setting up' the function first. | |
def counter(next_pid) do | |
receive do | |
n -> | |
next_pid <- n + 1 | |
end | |
end | |
def create_processes(n) do | |
# I thought of this like a domino. Enum.reduce 'prepares' all the processes | |
# by passing in the arguments to the functions. | |
last = Enum.reduce 1..n, self, | |
fn(_,send_to) -> spawn(Chain, :counter, [send_to]) end | |
# This is when the first 'domino' starts to topple the rest (i.e. kickstarts the chain reaction) | |
last <- 0 | |
# So how did we come to here? | |
# Recall what is passed as the first argument? 'self'! | |
# So, 'self' will be the very last to be sent the message. | |
# By then, we would have our answer ready. | |
receive do | |
final_answer -> | |
"Result is #{final_answer}" | |
end | |
end | |
def run(n) do | |
IO.puts inspect :timer.tc(Chain, :create_processes, [n]) | |
end | |
end |
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