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Comprehension in Python
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| my_dict = {i: i ** 2 for i in range(1, 11)} | |
| -> {1: 1, 2: 4, 3: 9, 4: 16, 5: 25, 6: 36, 7: 49, 8: 64, 9: 81, 10: 100} | |
| my_dict[7] | |
| -> 49 |
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| gen = (i ** i for i in range(1, 10)) | |
| print gen | |
| -> <generator object <genexpr> at 0xfc7d20> | |
| gen.next() | |
| -> 1 | |
| gen.next() | |
| -> 4 | |
| gen.next() | |
| -> 27 | |
| gen.next() | |
| -> 256 |
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| rows = cols = range(3) | |
| grid = [[(r, c) for c in cols] for r in rows] | |
| -> [[(0, 0), (1, 0), (2, 0)], | |
| [(0, 1), (1, 1), (2, 1)], | |
| [(0, 2), (1, 2), (2, 2)]] |
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| msg = [['M', 'J', 'S', 'F'], ['A', 'O', 'O', 'O'], ['K', 'H', 'M', 'O'], ['E', 'N', 'E', 'D']] | |
| ' '.join(''.join(msg[j][i] for j in range(4)) for i in range(4)) | |
| -> 'MAKE JOHN SOME FOOD' |
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| rows = cols = range(3) | |
| grid = [] | |
| for r in rows: | |
| for c in cols: | |
| if r != c: | |
| cell = (r, c) | |
| grid.append(cell) | |
| -> [(1, 0), (2, 0), (0, 1), (2, 1), (0, 2), (1, 2)] |
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| rows = cols = range(3) | |
| grid = [(r, c) for c in cols for r in rows] | |
| -> [(0, 0), (1, 0), (2, 0), (0, 1), (1, 1), (2, 1), (0, 2), (1, 2), (2, 2)] | |
| grid = [(r, c) for c in cols for r in rows if r != c] | |
| -> [(1, 0), (2, 0), (0, 1), (2, 1), (0, 2), (1, 2)] |
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| my_list = [i % 3 for i in range(10)] | |
| -> [0, 1, 2, 0, 1, 2, 0, 1, 2, 0] | |
| my_set = {i % 3 for i in range(10)} | |
| -> set([0, 1, 2]) |
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| squares = [] | |
| for n in range(10): | |
| squares.append(n ** 2) | |
| -> [0, 1, 4, 9, 16, 25, 36, 49, 64, 81] |
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| squares = [n ** 2 for n in range(10)] | |
| -> [0, 1, 4, 9, 16, 25, 36, 49, 64, 81] |
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| char_list = [c for c in 'abracadabra'] | |
| -> ['a', 'b', 'r', 'a', 'c', 'a', 'd', 'a', 'b', 'r', 'a'] | |
| char_set = {c for c in 'abracadabra'} | |
| -> set(['a', 'r', 'b', 'c', 'd']) |
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| sum(i ** 2 for i in range(10)) | |
| -> 285 |
hughdbrown
commented
Jan 28, 2013
Author
Well spotted - thanks for pointing it out. Now fixed!
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