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# Not thoroughly tested, but this seems to solve the problem recursively | |
class ChangeMaker | |
# in cents, so the below ints are equal to | |
# penny, nickle, dime, quarter, dollar, five, ten, twenty, fifty, a hundred | |
DENOMINATIONS = [1, 5, 10, 25, 100, 500, 1000, 2000, 5000, 10000] | |
def initialize(cost, tendered) | |
@cost = cost | |
@tendered = tendered | |
@difference = tendered - cost | |
@change ||= Hash.new(0) | |
end | |
def calculate_difference(n=-1) | |
return nil if @difference < 0 | |
return @change if @difference == 0 | |
subtract_from_difference(n) | |
calculate_difference(n-1) | |
end | |
def subtract_from_difference(n) | |
return if @difference < DENOMINATIONS[n] | |
@change[DENOMINATIONS[n]] += 1 | |
@difference -= DENOMINATIONS[n] | |
subtract_from_difference(n) | |
end | |
end | |
maker = ChangeMaker.new(1000, 5999) | |
p maker.calculate_difference | |
maker = ChangeMaker.new(1, 90000) | |
p maker.calculate_difference | |
# >> {2000=>2, 500=>1, 100=>4, 25=>3, 10=>2, 1=>4} | |
# >> {10000=>8, 5000=>1, 2000=>2, 500=>1, 100=>4, 25=>3, 10=>2, 1=>4} |
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