Using Array.reduce to sum a property in an array of objects

reduce-example.js

var accounts = [
  { name: 'James Brown', msgCount: 123 },
  { name: 'Stevie Wonder', msgCount: 22 },
  { name: 'Sly Stone', msgCount: 16 },
  { name: 'Otis Redding', msgCount: 300 }  // Otis has the most messages
];

// get sum of msgCount prop across all objects in array
var msgTotal = accounts.reduce(function(prev, cur) {
  return prev + cur.msgCount;
}, 0);

console.log('Total Messages:', msgTotal); // Total Messages: 461

Very nice! Thank you!

items = [
  { customer_id: 1, id: 1, sum: 123}
  { customer_id: 1, id: 2, sum: 321}
  { customer_id: 1, id: 3, sum: 213},
]
var total_sum = items.reduce(function(prev, cur) {
      return prev + cur.summ;
}, 0);

console.log(total_sum) -> `NaN` %(

Very nice. Thanks

Thank you!!

Simple and short... thanks

Great.

How to sum value only when the key 'name' that duplicate, sample:

var accounts = [
  { name: 'Blue', count: 2 },
  { name: 'Red', count: 3 },
  { name: 'Yellow', count: 4 },
  { name: 'Red', count: 5 }
];

And return:

var return = [
  { name: 'Blue', count: 2 },
  { name: 'Red', count: 8 },
  { name: 'Yellow', count: 4 }
];

@benwells @perdugames very clutch, thanks!

@everaldomatias have you found any solution to that please???

@James-n9ne4our i still haven't found the solution.

this is the genius solution!

In ES6: const msgTotal = accounts.reduce((prev, cur) => prev + cur.msgCount, 0);

Thanks dude!

Thanks - super useful!

Is it possible to use reduce if I have a calculation trough-out multiple properties like this:

var items = [
  { name: 'Item 1', amount: 123, discount: 0.1 },
  { name: 'Item 2', amount: 22, discount: 0.1 },
  { name: 'Item 3', amount: 16, discount: 0.2 },
  { name: 'Item 4', amount: 300, discount: 0 }
];

So I have to do something like this:

total = sum_all_items(amount - (amount * discount))

simplify it as total = sum_all_items(amount * (1 - discount))
OR
first, just make, discount = 1 - discount, and then, sum(amount * discount)

Banging. Nice one, mate.