Created
May 17, 2021 15:15
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Question: Find the n-upcount foa a given array.
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package com.hawa; | |
import lombok.extern.slf4j.Slf4j; | |
@Slf4j | |
/** | |
* Define the n-upcount of an array to be the number of times the partial sum goes from less | |
* than or equal to 'n' to greater than 'n' during the calculation of the sum of the elements of the array. | |
*/ | |
public class NUpCountProblem { | |
public static void main(String[] args) { | |
int[] num = {2, 3, 1, -6, 8, -3, -1, 2}; | |
int nUpCount = printNUpCount(num, 5); | |
log.info("The expected NUpCount is, {} ",nUpCount); | |
} | |
public static int printNUpCount(int[] a, int n){ | |
int partialSum = 0; | |
int nUpCount = 0; | |
for(int i=0; i<a.length; i++){ | |
partialSum = partialSum + a[i]; | |
if(partialSum > n){ | |
nUpCount = nUpCount + 1; | |
} | |
} | |
log.info("nUpCount :: {}", nUpCount); | |
return nUpCount; | |
} | |
} |
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