Julia Python microbenchmarks take 2

pyrunner.py

from timeit import timeit

A = timeit(setup = 'import test,random; n = range(10**6)', stmt = 'test.stress1(n)',
        number=5) / 5.0
B = timeit(setup = 'import test,random; n = range(10**6); random.shuffle(n)', 
        stmt = 'test.stress1(n)',
        number=5) / 5.0
C = timeit(setup='import test,random; n = [random.randint(0,100) for i in range(10**6)]', 
        stmt = 'test.stress1(n)',
        number=5) / 5.0
D = timeit(setup='import test,random; n = [random.randint(0,100000000) for i in range(10**6)]',
        stmt = 'test.stress1(n)',
        number=5) / 5.0
E = timeit(setup='import test', 
        stmt = 'test.stress_strings(10**6)',
        number=5) / 5.0

print("%15s %6.2fs %5.2fs %5.2fs %5.2fs %5.2fs" % ("Python", A, B, C, D, E))

test.jl

function stress1(keys::Array{Int,1})
    x = Dict{Int,Float64}()
    for i in keys
        x[i] = 0.0
    end
    return x
end

function stress_strings(n::Int)
    d = Dict{String,Int}()
    for i = 1:n
        d[string(i)] = i
    end
    return d
end

N = 10^6;

n = [1:N]; 
A = mean([@elapsed stress1(n) for i=1:5])

n = shuffle([1:N]); 
B = mean([@elapsed stress1(n) for i=1:5])

n = randi((0,100),N); 
C = mean([@elapsed stress1(n) for i=1:5])

n = randi((0,100000000),N); 
D = mean([@elapsed stress1(n) for i=1:5])

E = mean([@elapsed stress_strings(N) for i in 1:5])

@printf("%15s %6s %6s %6s %6s %6s\n", "","A","B","C","D","E")
println("----------------------------------------------------")
#@printf("%15s %6.2fs %5.2fs %5.2fs %5.2fs %5.2fs", "julia@3711a14090", A, B, C, D, E)
@printf("%15s %6.2fs %5.2fs %5.2fs %5.2fs %5.2fs", "^^ with IIT", A, B, C, D, E)

test.py

def stress_strings(n):
    d = {}
    for i in xrange(1,n):
        d[str(i)] = i
    return d

def stress1(keys):
    x = {}
    for i in keys:
        x[i] = 0.0
    return x