Created
November 23, 2014 09:55
-
-
Save binhngoc17/48ef5b7c14dde85a12c7 to your computer and use it in GitHub Desktop.
Break the tree into forest of event trees
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
import fileinput | |
inputs = fileinput.input() | |
input_vals = [] | |
for n in inputs: | |
input_vals.append(n.replace('\n', '')) | |
numVertices, numEdges = [int(k) for k in input_vals[0].split(' ')] | |
edges = [] | |
for i in range(numEdges): | |
edges.append(tuple([int(k) for k in input_vals[i+1].split(' ')])) | |
def find_node_group(i, edges, removedEdge): | |
count = 1 | |
stack = [i] | |
while stack: | |
item = stack.pop() | |
for edge in edges: | |
if edge in removedEdge: | |
continue | |
if edge[0] == item: | |
stack.append(edge[1]) | |
removedEdge.add(edge) | |
count += 1 | |
elif edge[1] == item: | |
stack.append(edge[0]) | |
removedEdge.add(edge) | |
count += 1 | |
return count | |
countEdges = 0 | |
for edge in edges: | |
group1NodesCount = find_node_group(edge[0], edges, set(tuple([edge]))) | |
group2NodesCount = find_node_group(edge[1], edges, set(tuple([edge]))) | |
if group2NodesCount % 2 == 0 and group1NodesCount % 2 == 0: | |
countEdges += 1 | |
print countEdges |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment