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ES5/ES6/ES2017/ES2019 omit & pick
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Object.keys(obj) | |
.filter((key) => ['blacklisted', 'keys'].indexOf(key) < 0) | |
.reduce((newObj, key) => Object.assign(newObj, { [key]: obj[key] }), {}) |
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Object.entries(obj) | |
.filter(([key]) => !['blacklisted', 'keys'].includes(key)) | |
.reduce((obj, [key, val]) => Object.assign(obj, { [key]: val }), {}); |
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Object.fromEntries( | |
Object.entries(obj) | |
.filter(([key]) => !['blacklisted', 'keys'].includes(key)) | |
); |
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Object.keys(obj) | |
.filter((key) => ['whitelisted', 'keys'].indexOf(key) >= 0) | |
.reduce((newObj, key) => Object.assign(newObj, { [key]: obj[key] }), {}) |
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Object.entries(obj) | |
.filter(([key]) => ['whitelisted', 'keys'].includes(key)) | |
.reduce((obj, [key, val]) => Object.assign(obj, { [key]: val }), {}); |
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Object.fromEntries( | |
Object.entries(obj) | |
.filter(([key]) => ['whitelisted', 'keys'].includes(key)) | |
); |
@kgstew It's good only for cases where only truthy values are useful, e.g. foo and bar are objects. Even better with destructuring:
const buildAnObjectFromAQuery = ({ foo, bar }) => ({
...foo && { foo },
...bar && { bar }
});
Another solution to omit
on a line can be:
const omit = (props, obj) => props.reduce((acc, key) => ((key, {[key]: _, ...rest}) => rest)(key, acc), obj)
Object.assign({}, ...['whitelisted', 'keys'].map(key => ({ [key]: obj[key] })))
This will not work if obj
is an empty object.
Typesafe omit:
export function omit<T extends object, K extends keyof T>(obj: T, paths: K[]): Omit<T, K> {
return {
...paths.reduce((mem, key) => ((k: K, { [k]: ignored, ...rest }) => rest)(key, mem), obj as object),
} as Omit<T, K>;
}
Another solution to pick
const pick = <T extends object, K extends keyof T>(
whitelisted: K[],
target: T,
defaultValue?: any
) =>
Object.fromEntries(
whitelisted.map((key) =>
[ key, key in target ? target[key] : defaultValue ]
)
);
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https://medium.com/@mikeh91/conditionally-adding-keys-to-javascript-objects-using-spread-operators-and-short-circuit-evaluation-acf157488ede