Created
May 9, 2013 12:03
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Dynamic Programming : Longest Common Subsequence
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public String lcs(String a, String b){ | |
int m = a.length(), n = b.length(); | |
int[][] f = new int[m+1][n+1]; | |
for (int i=0; i<=n; i++) | |
f[0][i] = 0; | |
for (int i=0; i<=m; i++) | |
f[i][0] = 0; | |
for (int i=1; i<=m; i++){ | |
for (int j=1; j<=n; j++){ | |
if (a.charAt(i-1) == b.charAt(j-1)) | |
f[i][j] = f[i-1][j-1] + 1; | |
else | |
f[i][j] = Math.max(f[i-1][j], f[i][j-1]); | |
} | |
} | |
// f[m][n] is the length of lcs | |
// construct lcs based on 2D array f | |
char[] lcs = new char[f[m][n]]; | |
int i = m, j = n, idx = f[m][n]-1; | |
while (f[i][j] != 0){ | |
if (f[i][j] == f[i][j-1]) | |
j--; | |
else if (f[i][j] == f[i-1][j]) | |
i--; | |
else{ | |
lcs[idx--] = a.charAt(i-1); | |
i--; | |
j--; | |
} | |
} | |
return new String(lcs); | |
} |
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