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求斐波那契数列的第n项的值,n的取值从1开始
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// 使用递归计算 | |
function fib(n) { return n < 2 ? n : fib(n-1) + fib(n-2) } | |
// 使用循环计算 | |
function fib_1(n) { | |
var arr = [1, 1] | |
var curLen | |
while(arr.length < n) { | |
curLen = arr.length | |
arr[curLen] = arr[curLen - 1] + arr[curLen - 2] | |
} | |
return arr[arr.length - 1] | |
} |
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