Zip image files from directory and send to email

sendmail.py

import os
import re
import zipfile
import smtplib
import sys
from email.MIMEMultipart import MIMEMultipart
from email.MIMEBase import MIMEBase
from email import Encoders


"""
	Required Input:
		- Source folder (src)
		- Archive name (dst)
		- SMTP information
		- Recipient email
"""
DIRECTORY_OF_IMAGES = "D:\Flat-UI-master\images\demo"
NAME_OF_DESTINATION_ARCHIVE = "test" # test.zip
SUBJECT = "Test Images Zipped"
RECIPIENTS = "[email protected], [email protected]" #separated by comma

server = "smtp.gmail.com"
port = 587
username = "[email protected]"
password = "fake"
sender = username
isGMAIL = True

# From http://stackoverflow.com/questions/14568647/create-zip-in-python
def zip(src, dst):
	zf = zipfile.ZipFile("%s.zip" % (dst), "w")
	src = os.path.abspath(src)
	for d, s, f in os.walk(src):
		for n in f:
			if re.match(r"^.*[.](png|jpg|gif|jpeg)$", n):
				abs_name = os.path.abspath(os.path.join(d,n))
				arc_name = abs_name[len(src) + 1:]
				zf.write(abs_name, arc_name)
	zf.close()


# From http://stackoverflow.com/questions/3362600/how-to-send-email-attachments-with-python

def sendMsg():
	msg = MIMEMultipart()
	msg['Subject'] = SUBJECT
	msg['From'] = sender
	msg['To'] = RECIPIENTS

	part = MIMEBase("application", "octet-stream")
	part.set_payload(open(NAME_OF_DESTINATION_ARCHIVE + ".zip", "rb").read())
	Encoders.encode_base64(part)
	part.add_header("Content-Disposition", "attachment; filename=\"%s.zip\"" % (NAME_OF_DESTINATION_ARCHIVE))
	msg.attach(part)

	smtp = smtplib.SMTP(server, port)
	if isGMAIL:
		smtp.ehlo()
		smtp.starttls()
		smtp.ehlo()
	smtp.login(username,password)
	smtp.sendmail(sender, RECIPIENTS, msg.as_string())
	smtp.close()

zip(DIRECTORY_OF_IMAGES, NAME_OF_DESTINATION_ARCHIVE)

try:
	sendMsg()
except Exception, exc:
    sys.exit( "mail failed; %s" % str(exc) )