A script that loads the given (list of) urls, waits for there to be a video tag on the page, then starts downloading the video using the page url as a filename (e.g http://example.com/my-show/episode-1 will produce my-show.episode-1.mp4)

getvideourl.py

#!/usr/bin/env python3
# pip install selenium, you probably want firefox as well or it won't work so good

import contextlib
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException
from subprocess import Popen
from sys import argv, stderr, stdin
from os import environ

if len(argv) > 1:
    if argv[1] == "-":
        urls = [line for line in stdin]
    else:
        urls = argv[1:]
    with contextlib.closing(webdriver.Firefox()) as driver:
        for i in urls:
            while True:
                try:
                    driver.get(i)
                    WebDriverWait(driver, 10).until(lambda driver: driver.find_element_by_tag_name('video'))
                    video = driver.find_element_by_tag_name("video").get_attribute("src")
                    show, title = driver.current_url.split("/")[-2:]
                    filename = "{}.{}.mp4".format(show, title[:title.index("?")])
                    driver.get("about:blank")
                    print("Getting {}".format(filename), file=stderr)
                    wget = Popen(["wget", "-O", filename, video])
                    wget.wait()
                except TimeoutException: # refreshes after ten seconds to try again
                    continue
                break