FizzBuzz in JavaScript

FizzBuzz.js

// for the numbers 1 through 20,
for (i=1; i<=100; i++) { 
 
  // if the number is divisible by both 3 and 5, write "FizzBuzz"
  if ( i % 3 ==0 && i % 5 == 0 ) { 
    console.log("FizzBuzz");
  }
 
  // if the number is divisible by 3, write "Fizz"
  else if ( i % 3 === 0 ) { 
    console.log("Fizz");
  }
  
  // if the number is divisible by 5, write "Buzz"
  else if ( i % 5 === 0){
    console.log("Buzz");
  }
  
  // otherwise, write just the number
  else {
    console.log(i);
  }
}

👍