Created
September 10, 2012 06:34
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| #!/bin/bash | |
| hoge="#" | |
| if [ $hoge!="#" ]; then | |
| echo "hoge is not # (1st)" | |
| fi | |
| if [ "$hoge " != "# " ]; then | |
| echo "hoge is not # (2nd)" | |
| fi | |
| # ダブルクォートで囲むだけでいいんじゃねーのって話 | |
| if [ "$hoge" != "#" ]; then | |
| echo "hoge is not # (3rd)" | |
| fi |
さっきのコメなし。
GNU bash, version 3.00.16(1)-release (i386-pc-solaris2.10) だと
hoge is not # (1st)
とだけ表示される。
GNU bash, version 4.1.5(1)-release (x86_64-pc-linux-gnu)でも同じ結果らしい。どうにもbashが != の比較なのに文字列としての比較じゃないことをしてるらしいとかなんとか。
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GNU bash, version 3.00.16(1)-release (i386-pc-solaris2.10) だと true って表示される。