Challenge: Find minimum in subarray

var indexOfMinimum = function(array, startIndex) {
    // Set initial values for minValue and minIndex,
    // based on the leftmost entry in the subarray:  
    var minValue = array[startIndex];
    var minIndex = startIndex;

    // Loop over items starting with startIndex, 
    // updating minValue and minIndex as needed:
    
    for (var i=minIndex+1; i<array.length; i++){
        if (array[i] < array[minIndex])
        {
            minIndex = i;
            minValue = array[i];
        }
    }
    
    return minIndex;
}; 

//declaring array
var array = [18, 6, 66, 44, 9, 22, 14];   
//passing array and variable to function
var index = indexOfMinimum(array, 2);

//  For the test array [18, 6, 66, 44, 9, 22, 14], 
//  the value 9 is the smallest of [..66, 44, 9, 22, 14]
//  Since 9 is at index 4 in the original array, 
//  "index" has value 4

//check 1
println("The index of the minimum value of the subarray starting at index 2 is " + index + "."  );
Program.assertEqual(index, 4);

//check 2
println("The index of the minimum value of the subarray starting at index 0 is " + indexOfMinimum(array, 0) + "."  );
Program.assertEqual(indexOfMinimum(array, 0), 1);

//check 3
println("The index of the minimum value of the subarray starting at index 5 is " + indexOfMinimum(array,5) + "."  );
Program.assertEqual(indexOfMinimum(array, 5), 6);