gistfile1.txt

function countMinimumOperations(password) {
  let operations = 0;
  let vowels = 0;
  let consonants = 0;

  // Count the number of vowels and consonants in the password
  for (let i = 0; i < password.length; i++) {
    const char = password[i];
    if ('aeiou'.includes(char)) {
      vowels++;
    } else {
      consonants++;
    }
  }
  
  return Math.abs(vowels - consonants);
}

// Example usage:
const password = "hack";
const result = countMinimumOperations(password);
 console.log(result);  // Output: 2


// https://www.codechef.com/FEB19B/problems/ARTBALAN
// Let's call a string balanced if all characters that occur in this string occur in it the same number of times.
// Find the minimum number of operations required to convert the given string to a balanced string.
// The absolute difference directly gives us the correct number of removals.
// h c k = 3 times
// a = 1 times
// 3 - 1 = 2
// aabbccddeeff 
// a a e e = 4 times
// b b c c d d f f = 8 times
// 8 - 4 = 4 times to a balanced string
// aabb 
// aa = 2 times
// bb = 2 times
// 2 - 2 = 0, it is already balanced

I think instead of Math.floor() maybe you should use Math.ceil() ?

doesn't work