Base64 encode/decode for Codea (Lua)

Base64.lua

-- Lua 5.1+ base64 v3.0 (c) 2009 by Alex Kloss <[email protected]>
-- licensed under the terms of the LGPL2

-- character table string
local b='ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/'

-- encoding
function enc(data)
    return ((data:gsub('.', function(x) 
        local r,b='',x:byte()
        for i=8,1,-1 do r=r..(b%2^i-b%2^(i-1)>0 and '1' or '0') end
        return r;
    end)..'0000'):gsub('%d%d%d?%d?%d?%d?', function(x)
        if (#x < 6) then return '' end
        local c=0
        for i=1,6 do c=c+(x:sub(i,i)=='1' and 2^(6-i) or 0) end
        return b:sub(c+1,c+1)
    end)..({ '', '==', '=' })[#data%3+1])
end

-- decoding
function dec(data)
    data = string.gsub(data, '[^'..b..'=]', '')
    return (data:gsub('.', function(x)
        if (x == '=') then return '' end
        local r,f='',(b:find(x)-1)
        for i=6,1,-1 do r=r..(f%2^i-f%2^(i-1)>0 and '1' or '0') end
        return r;
    end):gsub('%d%d%d?%d?%d?%d?%d?%d?', function(x)
        if (#x ~= 8) then return '' end
        local c=0
        for i=1,8 do c=c+(x:sub(i,i)=='1' and 2^(7-i) or 0) end
        return string.char(c)
    end))

looks like you need one more end line 35

in line 32 it mast be "for i=1,8 do c=c+(x:sub(i,i)=='1' and 2^(8-i) or 0) end" ?

Hey. how to add support for another language?

in line 32 it mast be "for i=1,8 do c=c+(x:sub(i,i)=='1' and 2^(8-i) or 0) end" ?

Yes it's 8. He didn't correct it yet

"yet"? It's a decade old and not my code - I just copied/pasted it here for a project long ago. 7 years ago rafis posted a link to a proper version. Go use that. FWIW - It worked when I used it way back when. YMMV.

Giỏi.yith"÷%(×'

Higiy