The only simple way to do SSH in Python today is to use subprocess + OpenSSH...

gistfile1.py

#!/usr/bin/python

# All SSH libraries for Python are junk (2011-10-13).
# Too low-level (libssh2), too buggy (paramiko), too complicated
# (both), too poor in features (no use of the agent, for instance)

# Here is the right solution today:

import subprocess
import sys

HOST="www.example.org"
# Ports are handled in ~/.ssh/config since we use OpenSSH
COMMAND="uname -a"

ssh = subprocess.Popen(["ssh", "%s" % HOST, COMMAND],
                       shell=False,
                       stdout=subprocess.PIPE,
                       stderr=subprocess.PIPE)
result = ssh.stdout.readlines()
if result == []:
    error = ssh.stderr.readlines()
    print >>sys.stderr, "ERROR: %s" % error
else:
    print result
    

SSH without third-party library

Here is my take on SSH without using third-party library. I leveraged a concept of fork system call in UNIX [1].

# Create an ssh session with python
import os
import shlex

def create_ssh(host, user):
  """Create a ssh session"""
  ssh = "/usr/bin/ssh -t {user}@{host} ".format(user=user, host=host)
 
  # Now, fork a child from current process 
  # This is a basic concept from Operating System class.
  pid = os.fork()
  if pid == 0:  # a child process
     print("Executing: %s" %(ssh))
     cmd = shlex.split(ssh)
     os.execv(cmd[0], cmd)
  
  os.wait(pid, 0)
  print("ssh session is finished. :)")
 
if __name__ == "__main__":
  create_ssh(
      host="remote_host", 
      user="remote_user")

Ref:
[1] https://en.wikipedia.org/wiki/Fork_(system_call)

Amazing

Still populating top three google results when searching for 'python3 connect ssh and run script' :)

Still true today. Amazing how badly libraries like paramiko and fabric fail at such a simple task.

Still a valid chain but still finding it hard to reliably send password from Osx or linux

thank you

Can tell how amazing it is when this solution still works today.
Thanks a lot.