Created
July 8, 2011 00:32
-
-
Save boucher/1070862 to your computer and use it in GitHub Desktop.
Parse months and years from a string
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
function parseExpirationDate(string) | |
{ | |
var components = string.split(/\b/); | |
var index = components.length; | |
var month, year; | |
// first we parse the words (so that month names can appear in any order) | |
while (index--) { | |
if (isNaN(parseInt(components[index]))) { | |
var candidateMonth = (new Date(components[index]+" 1, 2000")).getMonth(); | |
if (!isNaN(candidateMonth)) { | |
month = candidateMonth + 1; | |
} | |
components.splice(index, 1); | |
} | |
} | |
// then we parse numbers | |
index = components.length; | |
while (index--) { | |
var string = components[index]; | |
var number = parseInt(string); | |
if (string.length > 2 || number > 12) { | |
year = number; | |
} else if (year === undefined) { | |
year = number; | |
} else { | |
month = number; | |
} | |
} | |
if (year < 100) | |
year += Math.floor(new Date().getFullYear()/100)*100; | |
return { | |
month: month, | |
year: year, | |
success: !isNaN(new Date(["01", month || "_", year || "_"].join("/")).getTime()) | |
} | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment