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    Sorting multiple arrays in Javascript
  
        
  
    
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  | /** | |
| * Sorts all arrays together with the first. Pass either a list of arrays, or a map. Any key is accepted. | |
| * Array|Object arrays [sortableArray, ...otherArrays]; {sortableArray: [], secondaryArray: [], ...} | |
| * Function comparator(?,?) -> int optional compareFunction, compatible with Array.sort(compareFunction) | |
| */ | |
| function sortArrays(arrays, comparator = (a, b) => (a < b) ? -1 : (a > b) ? 1 : 0) { | |
| let arrayKeys = Object.keys(arrays); | |
| let sortableArray = Object.values(arrays)[0]; | |
| let indexes = Object.keys(sortableArray); | |
| let sortedIndexes = indexes.sort((a, b) => comparator(sortableArray[a], sortableArray[b])); | |
| let sortByIndexes = (array, sortedIndexes) => sortedIndexes.map(sortedIndex => array[sortedIndex]); | |
| if (Array.isArray(arrays)) { | |
| return arrayKeys.map(arrayIndex => sortByIndexes(arrays[arrayIndex], sortedIndexes)); | |
| } else { | |
| let sortedArrays = {}; | |
| arrayKeys.forEach((arrayKey) => { | |
| sortedArrays[arrayKey] = sortByIndexes(arrays[arrayKey], sortedIndexes); | |
| }); | |
| return sortedArrays; | |
| } | |
| } | 
  
    
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  | let people = ["john", "benny", "sally", "george"]; | |
| let peopleIds = [10, 20, 30, 40]; | |
| sortArrays([people, peopleIds]); | |
| [["benny", "george", "john", "sally"], [20, 40, 10, 30]] // output | |
| sortArrays({people, peopleIds}); | |
| {"people": ["benny", "george", "john", "sally"], "peopleIds": [20, 40, 10, 30]} // output | 
Thank you for taking the time to find and report everything wrong with this piece code.
I hope it gave you some relief.
I hope it gave you some relief.
the best therapy! even better than publishing a better version : P
😂
This is awesome. thanks.
  
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function sortArraysis a bad name .. how aboutparallelSort?default comparator is simply
(a, b) => (b - a)for ascending ordersort only looks for the sign (plus or minus), no need for +1 or -1
typeof arraysshould be array, sosortableArrayis alwaysarrays[0]dont rely on ordered map values .. when accepting objects-of-arrays, require the object-key to get sortableArray
let sortedIndexes = indexes.sort(.. sort mutates in-place AND returns, sosortedIndexes == indexes.map(is slower thanfor (let i = 0; ....) {.. especially in the hot-codefunction sortByIndexesvariable names are too similar, only adding
sis hard to read, addListfor example.. other than that, good job : )