Created
August 13, 2020 23:02
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# Definition for a binary tree node. | |
# class TreeNode | |
# attr_accessor :val, :left, :right | |
# def initialize(val = 0, left = nil, right = nil) | |
# @val = val | |
# @left = left | |
# @right = right | |
# end | |
# end | |
# @param {TreeNode} root | |
# @return {Void} Do not return anything, modify root in-place instead. | |
def flatten(node) | |
if node.nil? || (node.left.nil? && node.right.nil?) | |
return | |
end | |
unless node.left.nil? | |
flatten(node.left) | |
right = node.right | |
node.right = node.left | |
node.left = nil | |
current = node.right | |
while current.right | |
current = current.right | |
end | |
current.right = right | |
end | |
unless node.right.nil? | |
flatten(node.right) | |
end | |
return node | |
end |
def flatten(node)
if node.nil?
return
end
if node.left
flatten(node.left)
right = node.right
node.right = node.left
node.left = nil
current = node.right
while current.right
current = current.right
end
current.right = right
end
if node.right
flatten(node.right)
end
return node
end
Refactored version of first solution.
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