Created
May 8, 2012 08:03
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Given a string (provided as parameter), randomly flip ONE BIT in it.
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#include <stdio.h> | |
#include <stdlib.h> | |
#include <string.h> | |
#include <time.h> | |
void flip(char * str, int len) { | |
int byte, bit, bias; | |
char mask; | |
/* mmm, seeeds */ | |
srand(time(NULL)); | |
/* We want some bias towards the middle of the string. */ | |
bias = (len / 3); | |
byte = rand() % (len - (bias * 2)); | |
/* Construct a nice mask for this... */ | |
bit = rand() % (sizeof(char) * 8); | |
mask = 2 << bit; | |
str[byte] = str[byte] ^ mask; | |
} | |
int main(int argc, char ** argv) { | |
int i, cnt, offset, len; | |
char * str; | |
cnt = 0; | |
for(i = 1; i < argc; i++) { | |
cnt += strlen(argv[i]); | |
cnt++; // Space or end of line character. | |
} | |
/* Null-terminated, of course. */ | |
str = (char *)malloc(sizeof(char) * cnt); | |
memset(str, '\0', sizeof(char) * cnt); | |
offset = 0; | |
for(i = 1; i < argc; i++) { | |
len = strlen(argv[i]); | |
memcpy(str+offset, argv[i], len); | |
if(i < argc-1) { | |
str[offset+len] = ' '; | |
} | |
offset += len+1; | |
} | |
/* Randomly flip one of the bits in one of the characters. */ | |
flip(str, cnt); | |
printf("%s\n", str); | |
free(str); | |
return(0); | |
} |
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