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httpClient.DefaultRequestHeaders.Authorization = | |
new AuthenticationHeaderValue( | |
"Basic", | |
Convert.ToBase64String( | |
System.Text.ASCIIEncoding.ASCII.GetBytes( | |
string.Format("{0}:{1}", username, password)))); |
$header = "Authorization: Basic " . base64_encode($username . ':' . $password); |
base64string = base64.encodestring('%s:%s' % (username, password)).replace('\n', '') | |
header = ("Authorization: Basic %s" % base64string) |
$header = 'Authorization: Basic ' + Base64.encode64( username + ':' + password ).chomp |
$.ajax | |
({ | |
type: "GET", | |
url: "https://www.example.com", | |
dataType: 'json', | |
headers: { | |
"Authorization", btoa(username + ":" + password) | |
}, | |
data: '{}', | |
success: function (){ | |
... | |
} | |
}); |
var username = 'Test'; | |
var password = '123'; | |
var auth = 'Basic ' + new Buffer(username + ':' + password).toString('base64'); | |
var header = {'Host': 'www.example.com', 'Authorization': auth}; | |
var request = client.request('GET', '/', header); |
Ruby should use the strict_encode64 method otherwise using long usernames or passwords will end up with a line break:
$header = 'Authorization: Basic ' + Base64.strict_encode64( username + ':' + password ).chomp
Java + Spring Framework:
String authString = "Authorization: Basic " +
Base64Utils.encodeToString(
String.format("%s:%s", username,password)
.getBytes()
);
Vanilla Java:
String authString = "Authorization: Basic " +
Base64.getEncoder().encodeToString(
String.format("%s:%s", username,password)
.getBytes()
);
Node Aug '18 update:
const username = 'test',
password = 'supersecret01!',
auth = (Buffer.from(`${username}:${password}`).toString('base64')
Python3 update: encodestring
is deprecated (DeprecationWarning: encodestring() is a deprecated alias since 3.1, use encodebytes()
).
I think you should change the snippet to be:
base64string = base64.encodebytes(('%s:%s' % (username, password)).encode('utf8')).decode('utf8').replace('\n', '')
header = ("Authorization: Basic %s" % base64string)
or, if you prefer a bytes-like str:
base64string = base64.encodebytes(('%s:%s' % (username, password)).encode('utf8')).replace(b'\n', b'')
Perl:
'Authorization: Basic ' . MIME::Base64::encode("$username:$password")
Better Perl (avoid line breaks):
'Authorization: Basic ' . MIME::Base64::encode("$username:$password", '')
https://gist.github.com/brandonmwest/a2632d0a65088a20c00a#gistcomment-2345632
PowerShell
$username = 'test' $password = 'password' $base64AuthInfo = [convert]::ToBase64String([Text.Encoding]::ASCII.GetBytes(("{0}:{1} -f $username, $password"))) $base64AuthInfo
This in incorrect, the enclosing double quote should be after {1}, not $password.
$username = 'test' $password = 'password' $base64AuthInfo = [convert]::ToBase64String([Text.Encoding]::ASCII.GetBytes(("{0}:{1}" -f $username, $password))) $base64AuthInfo
In Free Pascal:
uses base64;
header := EncodeStringBase64(Concat(username, ':', password));
in Golang:
client := &http.Client{}
request, err := http.NewRequest("POST","https://example.com", nil)
encodedCredential := base64.StdEncoding.EncodeToString([]byte(fmt.Sprintf("%s:%s", CLIENT_ID, CLIENT_SECRET)))
request.Header.Add("Authorization", fmt.Sprintf("Basic %s", sEnc))
Line 7 correction for jquery snippet: "Authorization", "Basic " + btoa(username + ":" + password)
PowerShell
$username = 'test' $password = 'password' $base64AuthInfo = [convert]::ToBase64String([Text.Encoding]::ASCII.GetBytes(("{0}:{1} -f $username, $password"))) $base64AuthInfo
The code above doesn't work. Below is the fix.
$username = 'test'
$password = 'password'
$base64AuthInfo = [convert]::ToBase64String([Text.Encoding]::ASCII.GetBytes(("${username}:${password}")))
$base64AuthInfo
Scala:
val bytesFromString = (username ++ ":" ++ password).getBytes("UTF-8") val urlAuth = "Basic " ++ Base64.encode(bytesFromString)
The right scala implementation which run directly :
val tokenBytes = s"$username:$password".getBytes("UTF-8")
val tokenB64 = new String(java.util.Base64.getEncoder.encode(tokenBytes))
val token = s"Basic $tokenB64"
in JQuery, aren't we missing the 'Basic ' prefix?
in Rust;
use http_auth_basic::Credentials;
let credentials = Credentials::new("username", "password").as_http_header();
assert_eq!(String::from("Basic dXNlcm5hbWU6cGFzc3dvcmQ="), credentials);
In Elixir:
username = "username"
password = "password"
"#{username}:#{password}"
|> Base.encode64()
In kotlin:
val username = "username"
val password = "password
val userpass = username + ":" + password
val encodedAuth = encodeToString(userpass.toByteArray(), NO_WRAP)
val authHeaderValue = "Basic " + encodedAuth
httpURLConnection.setRequestProperty("Authorization", authHeaderValue)
In Salesforce APEX
HttpRequest request = new HttpRequest();
String username = 'test';
String password = 'test';
String accessToken = EncodingUtil.base64Encode(Blob.valueOf(username + ':' + password));
request.setHeader('Authorization', 'Basic ' + accessToken);
In oracle pl/sql
set serveroutput on;
DECLARE
v_str VARCHAR2(1000);
BEGIN
--Create encoded value
v_str := utl_encode.text_encode('Testuser:verySecret','WE8ISO8859P1', UTL_ENCODE.BASE64);
dbms_output.put_line(v_str);
--Decode the value..
v_str := utl_encode.text_decode(v_str,'WE8ISO8859P1', UTL_ENCODE.BASE64);
dbms_output.put_line(v_str);
END;
/
or
select utl_raw.cast_to_varchar2(utl_encode.base64_encode(utl_raw.cast_to_raw('Testuser:verySecret')))
from dual;
/
in JQuery, aren't we missing the 'Basic ' prefix?
+1
Dart:
final auth = "Basic " + BASE64.encode(UTF8.encode("${username}:${password}"));