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SVD-based Gaussian conjugate update
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import numpy as np | |
sigma2_true = 2.0 | |
def simulate_regression(N=100, M=1000): | |
X = np.random.normal(size=(N, M)) | |
beta_true = np.random.normal(size=(M,)) | |
y = X.dot(beta_true) + np.random.normal(0, np.sqrt(sigma2_true), size=(N,)) | |
return X, y, beta_true | |
X, y, beta_true = simulate_regression() | |
sigma2 = 2.0 | |
S_inv = np.eye(M) / sigma2 | |
omega2 = 0.2 | |
V_inv = np.eye(N) / omega2 | |
def naive_solve(X, y): | |
E = X.T.dot(V_inv).dot(X) + S_inv | |
beta_hat = np.linalg.solve(E, y.T.dot(X)) | |
return beta_hat | |
beta_hat_ref, *_ = np.linalg.lstsq(X, y) | |
beta_hat = naive_solve(X, y) | |
%timeit naive_solve(X, y) | |
# 26 ms ± 8.44 ms per loop (mean ± std. dev. of 7 runs, 1 loop each) | |
%timeit np.linalg.lstsq(X, y) | |
# 13 ms ± 1.02 ms per loop (mean ± std. dev. of 7 runs, 100 loops each) | |
# The norms against the true beta should be comparable | |
np.linalg.norm(beta_hat_ref - beta_true, 2) | |
np.linalg.norm(beta_hat - beta_true, 2) | |
U_X, d_X, V_X_T = np.linalg.svd(X, full_matrices=False) | |
R_X = U_X * d_X | |
S_inv_svd = np.eye(N) / sigma2 | |
def naive_svd_solve(X, y): | |
Z = R_X.T.dot(V_inv).dot(R_X) + S_inv_svd | |
eta_hat = np.linalg.solve(Z, y.T.dot(R_X)) | |
beta_hat = V_X_T.T.dot(eta_hat) | |
return beta_hat | |
beta_hat = naive_svd_solve(X, y) | |
np.linalg.norm(beta_hat_ref - beta_hat, 2) | |
np.linalg.norm(beta_hat - beta_true, 2) | |
%timeit naive_svd_solve(X, y) | |
# 298 µs ± 14.6 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each) | |
# This will take forever using the non-SVD approach | |
X, y, beta_true = simulate_regression(M=50000) | |
# This is only ever performed once for a given `X` | |
U_X, d_X, V_X_T = np.linalg.svd(X, full_matrices=False) | |
R_X = U_X * d_X | |
S_inv_svd = np.eye(X.shape[0]) / sigma2 | |
beta_hat = naive_svd_solve(X, y) | |
%timeit naive_svd_solve(X, y) | |
# 3.21 ms ± 114 µs per loop (mean ± std. dev. of 7 runs, 100 loops each) |
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