Solves the classic FizzBuzz problem in an aggressively functional programming style.

fizzbuzz.js

function arrayOfNumbers(n) {
    return Array.from(Array(n).keys())
        .map((x) => ++x)
}

function fizzBuzz(n) {

    const mutators = [
        {key: 3, val:"Fizz"},
        {key:5, val: "Buzz"}
    ];

    return arrayOfNumbers(n)
            .map((x) => {
                const words = mutators
                    .filter(({key}) => x % key === 0)
                    .map(({val}) => val);
                return words.length > 0 
                    ? words.join('') 
                    : `${x}`;
        }).join("\n");
};

console.log(fizzBuzz(15));