Created
October 19, 2011 05:05
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| first_array = [ 2, 1, 3] | |
| second_array = first_array | |
| second_array.sort! | |
| puts first_array # [ 1, 2, 3 ] | |
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I ran this by another rubyist out there and my misunderstanding came from the fact that the behavior of the = keyword. My expectation was that if you assign a value to second_array, at line 4 above, because it's all by reference it would change the value referenced by first_array as well. In fact, the = operator appears to create a new pointer and changes the reference of second_array from first_array to whatever you're now pointing it to.