Solve wordle superfast

wordle.py

#!/usr/bin/python3


# THIS CODE IS A MESSY QUICK AND DIRTY HACK
# AND WON'T BE COMMENTED FURTHER :)


import re
from collections import OrderedDict
from operator import itemgetter

with open('/usr/share/dict/american-english') as f:
    words = f.read()

wordls = re.findall('^[a-zA-Z]{5}$', words, re.MULTILINE)
wordls = [x.lower() for x in wordls]
wordls = sorted(wordls)

lettercount = { chr(i): 0 for i in range(ord('a'), ord('z')+1)}

for word in wordls:
    for i in word:
        lettercount[i] += 1

lettercount = OrderedDict(sorted(lettercount.items(), key = itemgetter(1), reverse = True))
print(lettercount)

wordls_string = "\n".join(wordls)
start_count = 0
while start_count < len(lettercount) - 5:
    loop_start = start_count
    for i in range(5, len(lettercount)):
        w_re = '^[{}]{{5}}$'.format(''.join(list(lettercount)[start_count:start_count + i]))

        perfect_word = re.findall(w_re, wordls_string, re.MULTILINE)
        perfect_word = [ w for w in perfect_word if len(set(list(w)))==5 ]
        if perfect_word:
            start_count = start_count + i
            print(perfect_word)
            break
    start_count = max(start_count, loop_start + 5)