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c00kiemon5ter/math.problem.mkdn

Created June 29, 2011 13:31
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where is your God now ?
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math.problem.mkdn

initial condition

a = b

* a

a2 = ab

+ a2 - 2ab

a2 + a2 - 2ab = ab + a2 - 2ab

grouping

2(a2 - ab) = a2 - ab

: (a2 - ab)

2 = 1

Where is your God now ?

@c00kiemon5ter

c00kiemon5ter commented Jun 29, 2011

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haha! :P

well, the fourth pass is : (a2 - ab)
which means divide by that term
where that term is a2 - ab = a2 - a2 = 0
and a and bare not some unrelated variables,
we know that a = b.

so it's actually zero , no matter what a and b are.
so that's not applicable
thus you end up with 2 = 1

which in turn is too bad, cause 0 = 0 looks like two cookies to me!
suddenly, cookies(!) everywhere(!!)

@pbrisbin

pbrisbin commented Jun 29, 2011

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Pfft, I said the magic phrase divide by zero, so I call that a cookie for me.

@Daenyth

Daenyth commented Jun 30, 2011

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Yeah, brisbin got it. I remember seeing this in high school. Old trick

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