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December 25, 2015 00:19
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import itertools,operator | |
ops=[operator.add,operator.sub,operator.mul,operator.div] | |
opCombs = list(itertools.product(ops,ops,ops)) | |
def customReduce(operators,nums): | |
total = nums[0] | |
for i in range(len(operators)): | |
if operators[i] == operator.div and nums[i+1]==0: | |
return 1000001 | |
if operators[i] == operator.div and total%nums[i+1]!=0: | |
return 1000001 | |
total = operators[i](total,nums[i+1]) | |
return total | |
#operators[0](operators[1](operators[2](nums[0],nums[1]),nums[2]),nums[3]) | |
f=open("4533.txt","r") | |
lines = [map(int,a.strip().split(" ")) for a in f if a.strip()!="0 0 0 0"] | |
print lines | |
for a in lines: | |
results = set() | |
perms = list(itertools.permutations(a,4)) | |
for b in perms: | |
for c in opCombs: | |
results.add(customReduce(c,b)) | |
d = sorted(list(results)) | |
print d | |
longestChain=0 | |
currentChain=0 | |
longestChainLastItem = 1000001 | |
lastItem = 1000001 | |
for b in d: | |
if b == lastItem+1: | |
currentChain+=1 | |
else: | |
if currentChain>longestChain: | |
longestChain = currentChain | |
longestChainLastItem = lastItem | |
currentChain=0 | |
else: | |
currentChain=0 | |
lastItem = b | |
print longestChainLastItem,longestChain | |
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