Created
April 19, 2016 02:39
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LeetCode - Shortest Word Distance III
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This is a follow up of Shortest Word Distance. The only difference is now word1 could be the same as word2. | |
// Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list. | |
// word1 and word2 may be the same and they represent two individual words in the list. | |
// For example, | |
// Assume that words = ["practice", "makes", "perfect", "coding", "makes"]. | |
// Given word1 = “makes”, word2 = “coding”, return 1. | |
// Given word1 = "makes", word2 = "makes", return 3. | |
// Note: | |
// You may assume word1 and word2 are both in the list. | |
public int shortestWordDistance(String[] words, String word1, String word2) { | |
if(words == null || words.length < 2) return -1; | |
int min = Integer.MAX_VALUE, i = -1, j = -1, pre = -1; | |
for(int k = 0; k < words.length; k++){ | |
if(words[k].equals(word1)) i = k; | |
if(words[k].equals(word2)) j = k; | |
if(i != -1 && j != -1){ | |
if(i != j) min = Math.min(Math.abs(i - j), min); | |
else{ | |
if(pre != -1) min = Math.min(Math.abs(i - pre), min); | |
pre = i; i = -1; j = -1; | |
} | |
} | |
} | |
return min; | |
} |
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