Created
April 13, 2016 19:00
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LeetCode - Closest Binary Search Tree Value
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| // Given a non-empty binary search tree and a target value, find the value in the BST that is closest to the target. | |
| // Note: | |
| // Given target value is a floating point. | |
| // You are guaranteed to have only one unique value in the BST that is closest to the target. | |
| // use successor and predecessor | |
| public int closestValue(TreeNode root, double target) { | |
| TreeNode successor = null, predecessor = null; | |
| while(root != null){ | |
| if(root.val > target){ | |
| successor = root; | |
| root = root.left; | |
| } else if(root.val < target) { | |
| predecessor = root; | |
| root = root.right; | |
| } else{ | |
| return root.val; | |
| } | |
| } | |
| if(successor == null && predecessor == null) return -1; | |
| if(successor == null) return predecessor.val; | |
| if(predecessor == null) return successor.val; | |
| if(Math.abs(target - successor.val) < Math.abs(target - predecessor.val)){ | |
| return successor.val; | |
| } else { | |
| return predecessor.val; | |
| } | |
| } | |
| // normal way | |
| public int closestValue(TreeNode root, double target) { | |
| if(root == null) return -1; | |
| int res = root.val; | |
| while(root != null){ | |
| if(Math.abs(root.val - target) < Math.abs(res - target)){ | |
| res = root.val; | |
| } | |
| root = root.val > target ? root.left : root.right; | |
| } | |
| return res; | |
| } |
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