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LeetCode - Search in Rotated Sorted Array
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| // | |
| public int search(int[] nums, int target) { | |
| if(nums == null || nums.length==0) return -1; | |
| int left = 0, right = nums.length-1; | |
| while(left <= right){ | |
| int mid = (left + right) / 2; | |
| if(nums[mid] == target){ | |
| return mid; | |
| }else if(nums[mid] >= nums[left]){ | |
| if(target >= nums[left] && nums[mid] > target){ | |
| right = mid - 1; | |
| }else{ | |
| left = mid + 1; | |
| } | |
| }else{ | |
| if(target > nums[mid] && target < nums[left]){ | |
| left = mid + 1; | |
| }else{ | |
| right = mid - 1; | |
| } | |
| } | |
| } | |
| return -1; | |
| } | |
| // | |
| public int search(int[] A, int target) { | |
| if(A==null || A.length==0) return -1; | |
| int left =0, right = A.length-1; | |
| while(left <= right){ | |
| int mid = (left+right)/2; | |
| if(A[mid] == target) return mid; | |
| if(A[mid]>=A[left]){ | |
| if(A[mid] > target && target>=A[left]) right = mid -1; | |
| else left = mid + 1; | |
| }else{ | |
| if(A[mid] < target && target<= A[right]) left = mid +1; | |
| else right = mid -1; | |
| } | |
| } | |
| return -1; | |
| } |
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